14x^2-9x+12=-2x^2+7x+8

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Solution for 14x^2-9x+12=-2x^2+7x+8 equation: 



14x^2-9x+12=-2x^2+7x+8

We move all terms to the left:

14x^2-9x+12-(-2x^2+7x+8)=0

We get rid of parentheses

14x^2+2x^2-7x-9x-8+12=0

We add all the numbers together, and all the variables

16x^2-16x+4=0

a = 16; b = -16; c = +4;
Δ = b2-4ac
Δ = -162-4·16·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{32}=1/2$

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